document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028038>Question 1028038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During strenuous exercise an athlete can burn 12 calories per minute on the treadmill and 8.5 calories per minute on the elliptical. The athlete uses both machines and burns 325 calories in 30 minutes. How many minutes does the athlete spend on each machine? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643215 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the minutes spent on the treadmill and elliptical, t and e.  Then we write<BR>\n" );
document.write( "t + e = 30<BR>\n" );
document.write( "12t + 8.5e = 325<BR>\n" );
document.write( "Now multiply the top one by 12 and subtract from the bottom one...we get<BR>\n" );
document.write( "12t + 8.5e = 325<BR>\n" );
document.write( "-(12t + 12e = 360)<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "-3.5e = -35<BR>\n" );
document.write( "e = 10 minutes on the elliptical which means<BR>\n" );
document.write( "t = 20 minutes on the treadmill </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );