document.write( "Question 1027995: AZra can do a job in 4 hoursthat halycycon can do in 3 hours and silfer can do in 2 hours. If the three can work together, how many hours would they finish the job? \n" ); document.write( "
Algebra.Com's Answer #643209 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "AZra can do a job in 4 hoursthat halycycon can do in 3 hours and silfer can do in 2 hours. If the three can work together, how many hours would they finish the job?
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document.write( "Azra makes \"1%2F4\" of the job per hour.\r\n" );
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document.write( "Halycycon makes \"1%2F3\" of the job per hour.\r\n" );
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document.write( "Silfer makes \"1%2F2\" of the job per hour.\r\n" );
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document.write( "Working together they make \"1%2F4+%2B+1%2F3+%2B+1%2F2\" = \"3%2F12+%2B+4%2F12+%2B+6%2F12\" = \"%283%2B4%2B6%29%2F12\" = \"13%2F12\" of the job per hour.\r\n" );
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document.write( "Hence, the three can make the job in \"12%2F13\" of an hour working together.\r\n" );
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\n" ); document.write( "\n" ); document.write( "See the lesson Using fractions to solve word problems on joint work in this site for the variety of solved joint-work problems.
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