document.write( "Question 1027652: Let f(x) be sqrt(3-x) where x <= 1, x^2 where 1= 3.
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\n" ); document.write( "limit of f(x) as x approaches 1-
\n" ); document.write( "limit of f(x) as x approaches 1+
\n" ); document.write( "limit of f(x) as x approaches 1
\n" ); document.write( "limit of f(x) as x approaches 3-
\n" ); document.write( "limit of f(x) as x approaches 3+
\n" ); document.write( "limit of f(x) as x approaches 3
\n" ); document.write( "limit of f(x) as x approaches 9
\n" ); document.write( "limit of f(x) as x approaches -6
\n" ); document.write( "Where is f discontinuous?
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Algebra.Com's Answer #643185 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The diagram helps to answer the questions.
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\n" ); document.write( "\"lim%28x-%3E1L%2Cf%28x%29%29=sqrt%282%29\"
\n" ); document.write( "\"lim%28x-%3E1R%2Cf%28x%29%29=1\"
\n" ); document.write( "\"lim%28x-%3E1%2Cf%28x%29%29=DNE\"<--- Does not exist
\n" ); document.write( "\"lim%28x-%3E3L%2Cf%28x%29%29=9\"
\n" ); document.write( "\"lim%28x-%3E3R%2Cf%28x%29%29=9\"
\n" ); document.write( "\"lim%28x-%3E3%2Cf%28x%29%29=9\"
\n" ); document.write( "\"lim%28x-%3E9%2Cf%28x%29%29=3\"
\n" ); document.write( "\"lim%28x-%3E-6%2Cf%28x%29%29=3%29\"
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\n" ); document.write( "Discontinuous at \"x=1\" since \"lim%28x-%3E1L%2Cf%28x%29%29%3C%3Elim%28x-%3E1R%2Cf%28x%29%29\"
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