document.write( "Question 1027803: Find the equation of the line perpendicular to y=7x+1 and passing at a distance of √2 from (4,-2). Then graph (i need it ASAP i beg of you) \n" ); document.write( "
Algebra.Com's Answer #643164 by Alan3354(69443)\"\" \"About 
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Find the equation of the line perpendicular to y=7x+1 and passing at a distance of sqrt(2) from (4,-2). Then graph (i need it ASAP i beg of you)
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\n" ); document.write( "Another method:
\n" ); document.write( "All points a distance of sqrt(2) from (4,-2) is a circle,
\n" ); document.write( "\"%28x-4%29%5E2+%2B+%28y%2B2%29%5E2+=+2\"
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\n" ); document.write( "Find the 2 points on the circle with a slope of the tangent of -1/7.
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\n" ); document.write( "m = -(x-h)/(y-k) for a circle with its center at (h,k)
\n" ); document.write( "(x-4)/(y+2) = 1/7
\n" ); document.write( "7x-28 = y+2
\n" ); document.write( "y = 7x-30
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\n" ); document.write( "Sub for y in \"%28x-4%29%5E2+%2B+%28y%2B2%29%5E2+=+2\" and solve for x, then y.
\n" ); document.write( "Then you have 2 points and a slope of -1/7\r
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