document.write( "Question 1027961: A takes 10 days less than the time taken by B to finish an embroidery work. If both A and B together can finish the work in 12 days. Find the time taken by B alone to finish the work. \n" ); document.write( "
Algebra.Com's Answer #643137 by mananth(16946)\"\" \"About 
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A x days
\n" ); document.write( "B x+ 10 days
\n" ); document.write( "A 1/x of the job in hour
\n" ); document.write( "B 1/(x+ 10 )of the job in 1 day
\n" ); document.write( "Together they take 1/x+ 1/(x+ 10 )of the job in 1 day
\n" ); document.write( "Together they do the job in 12 days 12 days
\n" ); document.write( "Together they do 1/ 12 of the job in 1 day
\n" ); document.write( "1/x + 1/(x+ 10 )= 1/ 12
\n" ); document.write( "LCD =x(x+ 10 )
\n" ); document.write( "(x+ 10 )+x= 1/ 12 (x + 10 )x
\n" ); document.write( "( 2 x+ 10 ) * 12 = x^2+ 10 x
\n" ); document.write( "24 x+ 120 = x^2+ 10 x
\n" ); document.write( "x^2 -14 x -120 = 0
\n" ); document.write( "Find the roots of the equation \r
\n" ); document.write( "\n" ); document.write( "x^2-20x+6x-120=0\r
\n" ); document.write( "\n" ); document.write( "x(x-20)+6(x-20)=0\r
\n" ); document.write( "\n" ); document.write( "(x-20)(x+6)=0\r
\n" ); document.write( "\n" ); document.write( "x= 20 OR -6\r
\n" ); document.write( "\n" ); document.write( "Ignore negative\r
\n" ); document.write( "\n" ); document.write( "x= 20\r
\n" ); document.write( "\n" ); document.write( "A takes 10 days
\n" ); document.write( "B takes 20 days to do the job alone
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