document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027968>Question 1027968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hollow metallic sphere of internal and external diameter 4 cm and 8 cm respectively is melted to form a solid cone of base diameter 8 cm . find the height of the cone </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643135 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume of metal available for cone = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%2F3%29%2Api%2A%28r1%5E3-r2%5E3%29 ALIGN=MIDDLE  ALT=\"%284%2F3%29%2Api%2A%28r1%5E3-r2%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "where r1= 4 and r2=2 cm (radii)\r<BR>\n" );
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document.write( "4^3-2^3= 56\r<BR>\n" );
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document.write( "V = (4/3) *pi *56 \r<BR>\n" );
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document.write( "V cone = 1/3 pi r^2 h\r<BR>\n" );
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document.write( "=(1/3) *pi *4^2*h\r<BR>\n" );
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document.write( "Equate the volumes to get h\r<BR>\n" );
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document.write( "(4/3) *pi *56 =(1/3) *pi *4^2*h\r<BR>\n" );
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document.write( "56=4h\r<BR>\n" );
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document.write( "h=14 cm<BR>\n" );
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