document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12621>Question 12621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi i have a question that reads 81+17x=30 and i have an answere of -3 can you tell me how to arrive at this answere as i can only get -2.133 thanx...... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6431 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 81+17x=30\r<BR>\n" );
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document.write( "Subtract 81 on both sides\r<BR>\n" );
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document.write( "81+17x-81=30-81 \r<BR>\n" );
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document.write( "17X = -51<BR>\n" );
document.write( "Dividing by 17 throughout<BR>\n" );
document.write( "X = -51/17 = -3 </SPAN>\n" );
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