document.write( "Question 1027926: Find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at
\n" ); document.write( "y = ±three divided by four times x..
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Algebra.Com's Answer #643096 by robertb(5830)\"\" \"About 
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The hyperbola would have the standard form of \"y%5E2%2F36+-+x%5E2%2Fb%5E2+=+1\", and we have to find b.\r
\n" ); document.write( "\n" ); document.write( "==> \"y%5E2+=+%2836%2Fb%5E2%29%28b%5E2%2Bx%5E2%29\"
\n" ); document.write( "==> y = ±\"%286%2Fb%29x\" (asymptotically) as x goes to \"infinity\".\r
\n" ); document.write( "\n" ); document.write( "==> \"6%2Fb+=+3%2F4\" ==> b = 8, and the standard form would be \"y%5E2%2F36+-+x%5E2%2F64+=+1\".
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