document.write( "Question 1027900: sin^2x-cos^2x=cosx
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Algebra.Com's Answer #643072 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"%281-cos%5E2%28x%29%29-cos%5E2%28x%29=cos%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1-2cos%5E2%28x%29-cos%28x%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2cos%5E2%28x%29%2Bcos%28x%29-1=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28x%29=%28-1%2B-+sqrt%281-4%2A2%2A%28-1%29%29%29%2F%282%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28x%29=%28-1%2B-+sqrt%289%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28x%29=%28-1%2B-+3%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28cos%28x%29=-1%2COR%2Ccos%28x%29=1%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x=180%2COR%2Cx=60%2COR%2Cx=300%29\"------degrees
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