document.write( "Question 1027866: If the perimeter of a rectangle is 46 cm and the area is 120 square cm, then what are the dimensions of the rectangle? \r
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Algebra.Com's Answer #643053 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "If the perimeter of a rectangle is 46 cm and the area is 120 square cm, then what are the dimensions of the rectangle?
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document.write( "Let x be the length and y be the width.\r\n" );
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document.write( "Then \r\n" );
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document.write( "x + y =  23,   (1)     ( 23 = \"46%2F2\" )\r\n" );
document.write( "xy    = 120.   (2)\r\n" );
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document.write( "Express x = 23 - y from (1) and substitute into (2). You will get\r\n" );
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document.write( "(23-y)*y = 120.\r\n" );
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document.write( "Solve this quadratic equation:\r\n" );
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document.write( "\"23y+-+y%5E2\" = \"120\",\r\n" );
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document.write( "\"y%5E2+-+23y+%2B+120\" = \"0\".\r\n" );
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document.write( "Factor the left side:\r\n" );
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document.write( "(x - 15)*(x-8) = 0.\r\n" );
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document.write( "The roots are 8 and 15.\r\n" );
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document.write( "The width, or shorter side is   8 cm.\r\n" );
document.write( "The length, or longer side is  15 cm.\r\n" );
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