document.write( "Question 1027714: A rectangular countertop has an area of 27 square feet. Its perimeter is 24 feet. What are the dimensions of the counter?\r
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Algebra.Com's Answer #643017 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "A rectangular countertop
\n" ); document.write( "has an area of 27 square feet.
\n" ); document.write( "Area = length x breadth
\n" ); document.write( "xy = 27.......(1)
\n" ); document.write( "x = 27/y.......(1)
\n" ); document.write( "Its perimeter is 24 feet.
\n" ); document.write( "Perimeter = 2 x width + 2 x length
\n" ); document.write( "24 = 2x + 2y
\n" ); document.write( "2x + 2y = 24.......(2)
\n" ); document.write( "Substitute x = 27/y into Eq(2)
\n" ); document.write( "2(27/y) + 2y = 24
\n" ); document.write( "54/y + 2y = 24
\n" ); document.write( "Multiply through by y
\n" ); document.write( "54 + 2y^2 = 24y
\n" ); document.write( "Sort into ax^2 + bx + c form
\n" ); document.write( "2y^2 - 24y + 54
\n" ); document.write( "Divide by 2
\n" ); document.write( "2(y^2 - 12y + 27)= 0
\n" ); document.write( "2(y - 3)(y - 9) = 0
\n" ); document.write( "y - 3 = 0
\n" ); document.write( "y = 3
\n" ); document.write( "y - 9 = 0
\n" ); document.write( "y = 9
\n" ); document.write( "By substituting either y = 3
\n" ); document.write( "back into Eq(1)
\n" ); document.write( "x = 27/y
\n" ); document.write( "x = 27/3
\n" ); document.write( "x = 9
\n" ); document.write( "or Substituting y = 9
\n" ); document.write( "back into Eq(1)
\n" ); document.write( "x = 27/y
\n" ); document.write( "x = 27/9
\n" ); document.write( "x = 3
\n" ); document.write( "So, either your breadth is 3ft
\n" ); document.write( "and the length is 9ft
\n" ); document.write( "or
\n" ); document.write( "breadth is 9ft
\n" ); document.write( "and the length is 3ft
\n" ); document.write( "Hope this helps :-)
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