document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027788>Question 1027788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a length of verandah is 3cm more than its breath.the numerical value of its atea is equal the numerical value of its perimeier.find the length of verandah </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643004 by </B><A HREF=/tutors/aboutme.mpl?userid=PURVI><B>PURVI(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=PURVI><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=PURVI><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643004\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 3 +B<BR>\n" );
document.write( "and L×B = 2(L+B)<BR>\n" );
document.write( "&#8658;(3+B)×B = 2[3+B +B] = 2(3+2B)<BR>\n" );
document.write( "&#8658;B²+3B = 6 +4B<BR>\n" );
document.write( "&#8658;B²- B -6 =0<BR>\n" );
document.write( "&#8658;B²-3B +2B -6 =0<BR>\n" );
document.write( "&#8658;B(B-3) + 2(B-3) =0<BR>\n" );
document.write( "&#8658;(B-3)(B+2)=0<BR>\n" );
document.write( "&#8756;B = 3 cm since value cannot be negative<BR>\n" );
document.write( "so length = 3+3 = 6 cm </SPAN>\n" );
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