document.write( "Question 1027772: Could someone please explain the formula for finding the 70th percentile if the mean is 2.9 and there is a standard deviation of 0.6? \n" ); document.write( "
Algebra.Com's Answer #642980 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The formula is\r
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\n" ); document.write( "\n" ); document.write( "Look up the Z value in your Normal Distribution table that corresponds to a probability of 70%, plug that number in along with your mean and standard deviation, and do the arithmetic.\r
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\n" ); document.write( "\n" ); document.write( "If you have Excel, you can type in: =NORM.S.INV(.7) to get the 70th percentile Z score. Or you could type in =NORM.INV(.7,2.9,.6) and get the value of directly.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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