document.write( "Question 1027739: Suppose that a cyclist began a 513 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 9.5 hours and the car traveled 38.2 mph faster than the bicycle, find the average rate of each \n" ); document.write( "
Algebra.Com's Answer #642971 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Suppose that a cyclist began a 513 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. \n" ); document.write( " If the bicycle and car met after 9.5 hours and the car traveled 38.2 mph faster than the bicycle, find the average rate of each \n" ); document.write( ": \n" ); document.write( "let s = the speed of the bicycle \n" ); document.write( "then \n" ); document.write( "(s+38.2) = the speed of the car \n" ); document.write( ": \n" ); document.write( "When they meet the sum of their distances will be 513 mi \n" ); document.write( "Write a distance equation; dist = time * speed \n" ); document.write( ": \n" ); document.write( "bike dist + car dist = 513 mi \n" ); document.write( "9.5s + 9.5(s+38.2) = 513 \n" ); document.write( "9.5s + 9.5s + 362.9 = 513 \n" ); document.write( "19s = 513 - 362.9 \n" ); document.write( "s = 150.1/19 \n" ); document.write( "s = 7.9 mph is the speed of the bike \n" ); document.write( "then \n" ); document.write( "7.9 + 38.2 = 46.1 mph is the speed of the car \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, find the sum of the actual distances each traveled \n" ); document.write( "9.5 *7.9 = 75.05 mi \n" ); document.write( "9.5*46.1 = 437.95 mi \n" ); document.write( "------------------------- \n" ); document.write( "total dist: 513.0 mi \n" ); document.write( " |