document.write( "Question 88446: I cannot figure out how to solve this quadratic equation.
\n" ); document.write( "Solve for x:\r
\n" ); document.write( "\n" ); document.write( "2x^2 + 3bx + b^2 = 0\r
\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Melody Salzer \n" ); document.write( "
Algebra.Com's Answer #64297 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, you can always use the quadratic formula to solve a quadratic equation: \"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"
\n" ); document.write( "But just to make it a little less confusing, we'll write your equation like this, with a B instead of a b:
\n" ); document.write( "\"2x%5E2%2B3Bx%2BB%5E2+=+0\" so...a = 2, b = 3B, and c = B^2
\n" ); document.write( "Now, making the appropriate substitutions, we get:
\n" ); document.write( "\"x+=+%28-3B%2B-sqrt%28%283B%29%5E2-4%282%29%28B%5E2%29%29%29%2F2%282%29\" Simplifying this, we have:
\n" ); document.write( "\"x+=+%28-3B%2B-sqrt%289B%5E2-8B%5E2%29%29%2F4\"
\n" ); document.write( "\"x+=+%28-3B%2B-sqrt%28b%5E2%29%29%2F4\"
\n" ); document.write( "\"x+=+%28-3B%2B-B%29%2F4\"
\n" ); document.write( "So the roots are:
\n" ); document.write( "\"x+=+%28-3B%2BB%29%2F4\" or \"x+=+-3B-B%29%2F4\"
\n" ); document.write( "\"x+=+-2B%2F4\" or \"x+=+-4B%2F4\"
\n" ); document.write( "\"x+=+-B%2F2\" or \"x+=+-B\"
\n" ); document.write( "But remember that we substituted the b in the original equation with B, so the answers are:
\n" ); document.write( "\"x+=+-b%2F2\" or \"x+=+-b\" \n" ); document.write( "
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