document.write( "Question 1027768: Ajit is three less than twice as old as Marie. If the sum of their ages is 39, determine their ages. Create a complete solution. \n" ); document.write( "

Algebra.Com's Answer #642964 by ikleyn(52803) $\"\"$ $\"About$

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\n" ); document.write( "Ajit is three less than twice as old as Marie. If the sum of their ages is 39, determine their ages. Create a complete solution.
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document.write( "A = 2M - 3,    (1)    (\"Ajit is three less than twice as old as Marie.\")\r\n" );
document.write( "A + M = 39.    (2)    (\"the sum of their ages is 39\")\r\n" );
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document.write( "Substitute A = 2M -3 from (1) into (2). You will get a single equation for M:\r\n" );
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document.write( "(2M - 3) + M = 39.\r\n" );
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document.write( "Simplify and solve it:\r\n" );
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document.write( "2M - 3 + M = 39,\r\n" );
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document.write( "3M = 39 + 3,\r\n" );
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document.write( "3M = 42,\r\n" );
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document.write( "M =  = 14.\r\n" );
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document.write( "Marie is 14 years. Ajit is 2M -3 = 2*14-3 = 28-3 = 25 years.\r\n" );
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