document.write( "Question 1027763: How many gallons each of 10% chloride solution and 30% chloride solution should be mixed in order to obtain 10 gallons of 25% chloride solutions? \n" ); document.write( "

Algebra.Com's Answer #642961 by ikleyn(52787) $\"\"$ $\"About$

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\n" ); document.write( "How many gallons each of 10% chloride solution and 30% chloride solution should be mixed in order to obtain 10 gallons of 25% chloride solutions?
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document.write( "Let x = the amount of the 10%  chloride solution needed (in gallons).\r\n" );
document.write( "The the amount of the 30%  chloride solution needed is (10-x) (in gallons).\r\n" );
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document.write( "The amount of the \"pure\" chloride in these solutions is 0.1*x + 0.3*(10-x).\r\n" );
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document.write( "It is exactly 25%, or 0.25 of 10 gallons, i.e. 0.25*10.\r\n" );
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document.write( "So, your \"pure chloride amount\" equation is \r\n" );
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document.write( "0.1*x + 0.3*(10-x) = 0.25*10.\r\n" );
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document.write( "Simplify and solve it for x:\r\n" );
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document.write( "0.1x + 3 - 0.3x = 2.5,\r\n" );
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document.write( "-0.2x = 2.5 - 3,\r\n" );
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document.write( "-0.2x = -0.5,\r\n" );
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document.write( "x =  = 2.5.\r\n" );
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document.write( "Answer. 2.5 gallons of 10% chloride solution and 7.5 = 10-2.5 gallons of 30% chloride solutions are needed.\r\n" );
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