document.write( "Question 1027660: The length of a rectangle is 5 more than the width. The area is 500 square inches. Find the length and width of the rectangle.
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Algebra.Com's Answer #642892 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 5 more than the width.\r
\n" ); document.write( "\n" ); document.write( "let the width be x
\n" ); document.write( "the length = (x+5)\r
\n" ); document.write( "\n" ); document.write( "x(x+5) =500\r
\n" ); document.write( "\n" ); document.write( "x^2+5x=500\r
\n" ); document.write( "\n" ); document.write( "x^2+5x-500=0\r
\n" ); document.write( "\n" ); document.write( "x^2+25z-20x-500=0\r
\n" ); document.write( "\n" ); document.write( "x(x+25)-20(x+25)=0\r
\n" ); document.write( "\n" ); document.write( "(x+25)(x-20)=0\r
\n" ); document.write( "\n" ); document.write( "x=20 the positive value\r
\n" ); document.write( "\n" ); document.write( "20 and 25 in are the dimensions\r
\n" ); document.write( "\n" ); document.write( " The area is 500 square inches.
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