document.write( "Question 88068: write an equation of a line that is parallel to y=-6x+4 and passes through(2,10).\r
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\n" ); document.write( "\n" ); document.write( "write an equation of line which is perpendicular to y=(-2/3)x-5 and passes through point (6,3).\r
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\n" ); document.write( "\n" ); document.write( "write the equation of three lines so that the y-intercept of each is -3. \n" ); document.write( "
Algebra.Com's Answer #64289 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
Y=-6X+4 NOW WE USE THE SLOPE(-6) BECAUSE THE LINE WE NEED IS PARALLEL TO THIS LINE THUS THEY HAVE THE SAME SLOPE AND THE X/Y COORDINATES (2,10) TO FIND THE Y INTERCEPT OF THIS LINE THUS:
\n" ); document.write( "2=-6*2+b
\n" ); document.write( "2=-12+b
\n" ); document.write( "b=2+12
\n" ); document.write( "b=14 THE Y INTERCEPT.
\n" ); document.write( "THIS GIVES US THE LINE EQUATION OF:
\n" ); document.write( "Y=-6X+14 ANSWER.
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\n" ); document.write( "Y=-2X/3-5 THIS LINE HAS A SLOPE OF (-2/3) THUS THE LINE PERPENDICULAR TO THIS LINE MUST HAVE A SLOPE OF (3/2) THE NEGATIVE RECIPRICAL.
\n" ); document.write( "NOW USING THE POINTS(6,3) WE USE THE LINE FORMULA Y=mX+b TOP FIND THE Y INTERCEPT(b) THUS:
\n" ); document.write( "3=3/2*6+b
\n" ); document.write( "3=9+b
\n" ); document.write( "b=3-9
\n" ); document.write( "b=-6 SO THE LINE EQUATION OF THIS PERPENDICULAR LINE THROUGH (6,3) IS:
\n" ); document.write( "Y=2X/3-6 ANSWER.
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\n" ); document.write( "Y=2X-3
\n" ); document.write( "Y=-5X/7-3
\n" ); document.write( "Y=18X/35-3
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