document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027601>Question 1027601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Marie invested $12,000 in two different simple interest accounts.  She invested part of the money at 8% and the rest at 6%.  How much was invested at each amount, if the total interest earned was $872?  State what x represents, state the equation, and then state the answer.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642847 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642847\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount invested at 8%.  Thus 12000-x would be the amount invested at 6%.  The setup looks like this:<BR>\n" );
document.write( ".08x + .06(12000-x) = 872<BR>\n" );
document.write( "Now solve for x.<BR>\n" );
document.write( ".08x + 720 - .06x = 872<BR>\n" );
document.write( ".02x + 720 = 872<BR>\n" );
document.write( ".02x = 152<BR>\n" );
document.write( "x = $7600 invested at 8%<BR>\n" );
document.write( "12000-x = $4400 invested at 6% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );