document.write( "Question 88435: Hello, I am having diffuclties understanding this problem. \r
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document.write( "Find all real and imaginary zeros for each polynomial factor.
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document.write( "f(x) = 2x^2-1=0\r
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document.write( "Here is the work that I have started with but I am unsure if I am doing this properly\r
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document.write( "2x^2-1=0
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document.write( "+1 = +1
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document.write( "2x^2=1
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document.write( "2\r
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document.write( "x^2=1/2\r
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document.write( "would my answer be x= square root of +1/2 and square root of -1/2? \r
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document.write( "Thank you for your help \n" );
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Algebra.Com's Answer #64283 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Now let's use the quadratic formula to solve for x:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So lets solve \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which simplifies to \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the roots approximate to\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So our solutions are:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice when we graph \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "note:\r \n" ); document.write( "\n" ); document.write( "Since |