document.write( "Question 1027573: Let f be a function such that f(0) = 2 and f'(x)<=6 for -10<=x<=10.\r
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document.write( "A) What is the maximum possible value of f(4)?
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document.write( "B) What is the maximum possible value of f(2)?
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document.write( "C) Can f(5) be negative? Can f(5) = 0? Why or Why not?
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document.write( "D) Can f(5) = 31? Can f(5) = 35? Why or why not? \n" );
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Algebra.Com's Answer #642786 by robertb(5830)![]() ![]() You can put this solution on YOUR website! By the mean value theorem,\r \n" ); document.write( "\n" ); document.write( "there is a \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "A) ==> \n" ); document.write( "\n" ); document.write( "B) ==> \n" ); document.write( "\n" ); document.write( "C) Can f(5) be negative? YES. The derivative in the neighborhood around x = 5 can be negative enough (and hence the graph fall drastically enough) so as to warrant the graph of of f(x) to cross the x-axis before x = 5. (Remember, f'(x) is less than or equal to 6 in [-10,10].)\r \n" ); document.write( "\n" ); document.write( "Can f(5) = 0? YES, by a reasoning very similar to the preceding paragraph.\r \n" ); document.write( "\n" ); document.write( "D) Can f(5) = 31? YES. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can f(5) = 35? NO. The highest f(5) can get is 32 \n" ); document.write( " |