document.write( "Question 1027471: 1
\n" ); document.write( "a sector of circle radius 7cm subtending an angle of 270° at the center of the circle,is used to form cone.
\n" ); document.write( "a:find the base radius of the cone.
\n" ); document.write( "b:calculate the area of the base of the cone correct to the nearest square centimetres. ( take π=22/7).
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Algebra.Com's Answer #642754 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Angle/360 = Length of arc/Pi x diameter.
\n" ); document.write( "270/360 = Length of arc/Pi x 14
\n" ); document.write( "Length of arc = (270 x Pi x 14)/360
\n" ); document.write( "Length of arc = 32.99cm.(2 decimal places)
\n" ); document.write( "When the sector is folded into a cone
\n" ); document.write( "the arc length becomes the cone's
\n" ); document.write( "circumference.
\n" ); document.write( "Circumference = Pi x diameter.
\n" ); document.write( "32.99 = Pi x diameter.
\n" ); document.write( "Diameter = 32.99/Pi
\n" ); document.write( "Diameter = 10.5cm
\n" ); document.write( "Diameter = 2 x radius
\n" ); document.write( "Radius = Diameter/2
\n" ); document.write( "Radius = 10.5/2
\n" ); document.write( "Radius = 5.25cm
\n" ); document.write( "b) Area of base of cone = Pi x radius^2
\n" ); document.write( "Area = Pi x 5.25^2
\n" ); document.write( "Area = 86.59cm^2
\n" ); document.write( "Area = 87cm^2 (nearest whole square centimetre)
\n" ); document.write( "Hope this helps :-)
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