document.write( "Question 1027471: 1
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document.write( "a sector of circle radius 7cm subtending an angle of 270° at the center of the circle,is used to form cone.
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document.write( "a:find the base radius of the cone.
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document.write( "b:calculate the area of the base of the cone correct to the nearest square centimetres. ( take π=22/7).
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Algebra.Com's Answer #642754 by Cromlix(4381) You can put this solution on YOUR website! Hi there, \n" ); document.write( "Angle/360 = Length of arc/Pi x diameter. \n" ); document.write( "270/360 = Length of arc/Pi x 14 \n" ); document.write( "Length of arc = (270 x Pi x 14)/360 \n" ); document.write( "Length of arc = 32.99cm.(2 decimal places) \n" ); document.write( "When the sector is folded into a cone \n" ); document.write( "the arc length becomes the cone's \n" ); document.write( "circumference. \n" ); document.write( "Circumference = Pi x diameter. \n" ); document.write( "32.99 = Pi x diameter. \n" ); document.write( "Diameter = 32.99/Pi \n" ); document.write( "Diameter = 10.5cm \n" ); document.write( "Diameter = 2 x radius \n" ); document.write( "Radius = Diameter/2 \n" ); document.write( "Radius = 10.5/2 \n" ); document.write( "Radius = 5.25cm \n" ); document.write( "b) Area of base of cone = Pi x radius^2 \n" ); document.write( "Area = Pi x 5.25^2 \n" ); document.write( "Area = 86.59cm^2 \n" ); document.write( "Area = 87cm^2 (nearest whole square centimetre) \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |