document.write( "Question 1027389: A rectangular piece of metal is 10 in longer than it is wide. Squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 528in^3, what were the original dimensions of the piece of metal? \n" ); document.write( "
Algebra.Com's Answer #642745 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let width of metal plate be x \n" ); document.write( "length = x+10\r \n" ); document.write( "\n" ); document.write( "after cutting the corners\r \n" ); document.write( "\n" ); document.write( "width = (x-4) \n" ); document.write( "and \r \n" ); document.write( "\n" ); document.write( "Length = (x+10)-4= x+6\r \n" ); document.write( "\n" ); document.write( "The height will be 2 inches\r \n" ); document.write( "\n" ); document.write( "Volume = L * W * H\r \n" ); document.write( "\n" ); document.write( "(x-4)(x+6)*2=528\r \n" ); document.write( "\n" ); document.write( "(x-4)(x+6) = 264\r \n" ); document.write( "\n" ); document.write( "x^2+2x-24=264\r \n" ); document.write( "\n" ); document.write( "x^2+2x =288\r \n" ); document.write( "\n" ); document.write( "x^2+2x+1= 288\r \n" ); document.write( "\n" ); document.write( "(x+1)^2=289\r \n" ); document.write( "\n" ); document.write( "take the square root\r \n" ); document.write( "\n" ); document.write( "(x+1) = +/- 17\r \n" ); document.write( "\n" ); document.write( "x= 16 or -18\r \n" ); document.write( "\n" ); document.write( "ignore negative \r \n" ); document.write( "\n" ); document.write( "width = 16in and length = 26in \n" ); document.write( " |