document.write( "Question 1027528: Could you assist me in solving a problem please? I can solve every problem in Chapter 2 of my daughter’s college algebra book except one and its bothering me. The surface area \"S\" of a right circular cylinder is given by the formula \"S\" = 2πrh + 2πr^2. If the height is twice the radius, find each of the following: a) A function S(r) for the surface area as a function of r. b) A function S(h) for the surface area as a function of h. That's it. When I solve for h in the original equation its equal to -r in order to plug it back into the Volume formula to solve for V(r). How can h be equal to -r and 2r as suggested in the word problem? I am missing something and I simply don't know what it is. Thank you.
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Algebra.Com's Answer #642740 by josgarithmetic(39620)\"\" \"About 
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\"system%28S=2%2Api%2Arh%2B2%2Api%2Ar%5E2%2Ch=2r%29\"
\n" ); document.write( "THE SECOND EQUATION IS IN THE PROBLEM DESCRIPTION!!\r
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\n" ); document.write( "\n" ); document.write( "(a) Find the function S(r), surface area as a function or r.
\n" ); document.write( "SUBSTITUTE FOR h ACCORDING TO THE PROBLEM DESCRIPTION:
\n" ); document.write( "\"S%28r%29=2%2Api%2Ar%282r%29%2B2%2Api%2Ar%5E2\" through substitution;
\n" ); document.write( "\"S%28r%29=2%2A2%2Api%2Ar%2Ar%5E2%2B2%2Api%2Ar%5E2\"
\n" ); document.write( "\"highlight%28S%28r%29=4%2Api%2Ar%5E3%2B2%2Api%2Ar%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "(b) Find surface area as a function of cylinder height, h.
\n" ); document.write( "-
\n" ); document.write( "\"h=2r\"
\n" ); document.write( "\"h%2F2=2r%2F2\"
\n" ); document.write( "\"h%2F2=r\"
\n" ); document.write( "-
\n" ); document.write( "Substitute for h in S.
\n" ); document.write( "\"S%28h%29=2%2Api%28h%2F2%29%2Ah%2B2%2Api%2A%28h%2F2%29%5E2\"
\n" ); document.write( "\"S%28h%29=2%2Api%2Ah%2Ah%2F2%2B2%2Api%2Ah%5E2%2F%282%2A2%29\"
\n" ); document.write( "\"highlight%28S%28h%29=pi%2Ah%5E2%2B%28pi%2Ah%5E2%29%2F2%29\"
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