document.write( "Question 1027528: Could you assist me in solving a problem please? I can solve every problem in Chapter 2 of my daughter’s college algebra book except one and its bothering me. The surface area \"S\" of a right circular cylinder is given by the formula \"S\" = 2πrh + 2πr^2. If the height is twice the radius, find each of the following: a) A function S(r) for the surface area as a function of r. b) A function S(h) for the surface area as a function of h. That's it. When I solve for h in the original equation its equal to -r in order to plug it back into the Volume formula to solve for V(r). How can h be equal to -r and 2r as suggested in the word problem? I am missing something and I simply don't know what it is. Thank you.
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Algebra.Com's Answer #642740 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "THE SECOND EQUATION IS IN THE PROBLEM DESCRIPTION!!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(a) Find the function S(r), surface area as a function or r. \n" ); document.write( "SUBSTITUTE FOR h ACCORDING TO THE PROBLEM DESCRIPTION: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(b) Find surface area as a function of cylinder height, h. \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "Substitute for h in S. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |