document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027409>Question 1027409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 7m less than three times the width. If the length is decreased by 5 and the width by three,the perimeter will be 90m. Find the dimensions of the original rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642727 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 7m less than three times the width.<BR>\n" );
document.write( "width =x<BR>\n" );
document.write( "length = 3x-7\r<BR>\n" );
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document.write( " If the length is decreased by 5 => (3x-7)-5 = 3x-12\r<BR>\n" );
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document.write( " and the width by three, => x-3\r<BR>\n" );
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document.write( "the perimeter will be 90m.\r<BR>\n" );
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document.write( "2( (3x-12)+(x-3)=90\r<BR>\n" );
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document.write( "2(4x-15)=90\r<BR>\n" );
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document.write( "4x-15 = 45<BR>\n" );
document.write( "4x=60<BR>\n" );
document.write( "x=15\r<BR>\n" );
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document.write( "find length </SPAN>\n" );
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