document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027439>Question 1027439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carter has three times as many nickels as quarters and three more dimes than nickels. If the total face value of these coins is $3.80, how many dimes does Carter have? Define your variables, set up the equations, and solve. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642725 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642725\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Carter has three times as many nickels as quarters\r<BR>\n" );
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document.write( "Quarters = q\r<BR>\n" );
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document.write( "Nickels = 3q\r<BR>\n" );
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document.write( " and three more dimes than nickels.\r<BR>\n" );
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document.write( "3q+3\r<BR>\n" );
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document.write( " If the total face value of these coins is $3.80, = 380 cents\r<BR>\n" );
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document.write( "25q+5*3q+10*(3q+3)=380\r<BR>\n" );
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document.write( "25q+15q+30q+30=380\r<BR>\n" );
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document.write( "70q=350\r<BR>\n" );
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document.write( "q= 5\r<BR>\n" );
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document.write( "dimes = (3q+3) = 18  </SPAN>\n" );
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