document.write( "Question 1027372: Distance between two stations X and Y is 220 km. Trains P and Q leave station X at 8 am and 9.51 am respectively at the speed of 25 km/hr and 20 km/hr respectively for journey towards Y. Train R leaves station Y at 11.30 am at a speed of 30 km/hr for journey towards X. When and where will P be at equal
\n" ); document.write( "distance from Q and R ?
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Algebra.Com's Answer #642711 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The time taken by P, Q, R to reach some point enroute is the same.
\n" ); document.write( "They start at different times and speeds\r
\n" ); document.write( "\n" ); document.write( "Equate time of P & Q
\n" ); document.write( "Equate time of P & r\r
\n" ); document.write( "\n" ); document.write( "and solve the equations\r
\n" ); document.write( "\n" ); document.write( "P &Q\r
\n" ); document.write( "\n" ); document.write( "(x+d)/25 = x/20 + 1 51/60\r
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\n" ); document.write( "\n" ); document.write( "(x+d)/25 -x/20 = 37/20\r
\n" ); document.write( "\n" ); document.write( "20x+20d -25x = 37*20*25/20\r
\n" ); document.write( "\n" ); document.write( "-5x +20d = 925
\n" ); document.write( "/-5
\n" ); document.write( "x-4d= -185.......................(1)\r
\n" ); document.write( "\n" ); document.write( "P& R
\n" ); document.write( "(x+d)/25 = (220-x-2d)/30 +7/2\r
\n" ); document.write( "\n" ); document.write( "(x+d)/25 -(220-x-2d)/30 =7/2\r
\n" ); document.write( "\n" ); document.write( "30x+30d -25*220+25x+50d = 30*25*7/2\r
\n" ); document.write( "\n" ); document.write( "55x+80d =8125......................(2)\r
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\n" ); document.write( "\n" ); document.write( "V1.00 x -4.00 d = -185.00 .............1
\n" ); document.write( "Total value
\n" ); document.write( "55.00 x + 80.00 d = 8125.00 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 20.00
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "20.00 x -80.00 d = -3700.00
\n" ); document.write( "55.00 x + 80.00 d = 8125.00
\n" ); document.write( "Add the two equations
\n" ); document.write( "75.00 x = 4425.00
\n" ); document.write( "/ 75.00
\n" ); document.write( "x = 59.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1.00 x -4.00 d = -185.00
\n" ); document.write( "59.00 -4.00 d = -185.00
\n" ); document.write( " -4.00 d = -185.00 -59.00
\n" ); document.write( " -4.00 d = -244.00
\n" ); document.write( " d = 61.00 \r
\n" ); document.write( "\n" ); document.write( "you can calculate real time easily \r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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