document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12548>Question 12548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation for each line. then graph the line. <BR>\n" );
document.write( "Through (-1,3) and parallel to y=2x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6427 by </B><A HREF=/tutors/aboutme.mpl?userid=AdolphousC><B>AdolphousC(70)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AdolphousC><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you are starting with the equation y = 2x + 1, you know you need to find a line parallel to it, parallel lines have the same slope but different y intercept, so you are going to use y = 2x + b as your parallel line, using the point ( -1, 3 ) to find b.<BR>\n" );
document.write( "<P>\r<BR>\n" );
document.write( "\n" );
document.write( "y = 2x + b Substitute<BR>\n" );
document.write( "3 = (2*-1)+b Simplify<BR>\n" );
document.write( "3 = -2 + b Add 2 on both sides<BR>\n" );
document.write( "b = 5<BR>\n" );
document.write( "so your parallel line has the equation y = 2x + 5<BR>\n" );
document.write( "<P>\r<BR>\n" );
document.write( "\n" );
document.write( "now graph, they should look like this...<BR>\n" );
document.write( "<BR><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C200%2C+-10%2C10%2C-10%2C10%2C+2x+%2B+1%2C+2x+%2B+5%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C200%2C+-10%2C10%2C-10%2C10%2C+2x+%2B+1%2C+2x+%2B+5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );