document.write( "Question 1027427: I am having issues with word problems, just not sure how to set them up and then complete. \r
\n" ); document.write( "\n" ); document.write( "Radioactive carbon-14 decays according to the function Q(t)=Q0e^-0.000121t where t is time in years, Q(t) is the quantity remaining at time t, and Q0 is the amount present at t=0. Estimate the age of bone fragment if 17% of the original quantity of carbon-14 remains.\r
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Algebra.Com's Answer #642656 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
They are saying that \"+Q%28t%29+=+.17Q%280%29+\". This means,
\n" ); document.write( "at present, you have 17% of the amount you started with
\n" ); document.write( "which was \"+Q%280%29+\"
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\n" ); document.write( "Now I can rewrite the formula:
\n" ); document.write( "\"+Q%28t%29+=+Q%280%29%2Ae%5E%28-.000121t+%29+\"
\n" ); document.write( "\"+.17Q%280%29+=+Q%280%29%2Ae%5E%28-.000121t+%29+\"
\n" ); document.write( "Now divide both sides by \"+Q%280%29+\"
\n" ); document.write( "\"+.17+=+e%5E%28-.000121t+%29+\"
\n" ); document.write( "Take the natural log of both sides
\n" ); document.write( "\"+ln%28+.17+%29+=+-.000121t+\"
\n" ); document.write( "\"+-1.772+=+-.000121t+\"
\n" ); document.write( "\"+t+=+1.772+%2F+.000121+\"
\n" ); document.write( "\"+t+=+14644.628+\"
\n" ); document.write( "The age is 14,645 years
\n" ); document.write( "Check my math & maybe get another opinion
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