document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88429>Question 88429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of x.\r<BR>\n" );
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document.write( "x=3s<BR>\n" );
document.write( "x=(a+15)<BR>\n" );
document.write( "s=(a-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64265 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are several ways you can do this problem. Here's one way.<BR>\n" );
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document.write( "You are told that x = 3s and also that x = a + 15. Therefore, you can tell that since<BR>\n" );
document.write( "3s equals x and a + 15 equals x, then 3s must also equal a + 15. In equation form this is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3s+=+a+%2B+15 ALIGN=MIDDLE  ALT=\"3s+=+a+%2B+15\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solve this equation for s by dividing both sides by 3 to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+%28a+%2B+15%29%2F3 ALIGN=MIDDLE  ALT=\"s+=+%28a+%2B+15%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Then you are also told that s = a - 1. So you can substitute a - 1 for s in the equation to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+-+1+=+%28a+%2B+15%29%2F3 ALIGN=MIDDLE  ALT=\"a+-+1+=+%28a+%2B+15%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Get rid of the denominator by multiplying all terms on both sides by 3 to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3a+-+3+=+a+%2B+15 ALIGN=MIDDLE  ALT=\"3a+-+3+=+a+%2B+15\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Subtract a from both sides and the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2a+-+3+=+15 ALIGN=MIDDLE  ALT=\"2a+-+3+=+15\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Add 3 to both sides:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2a+=+18 ALIGN=MIDDLE  ALT=\"2a+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solve for a by dividing both sides by 2:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+=+9 ALIGN=MIDDLE  ALT=\"a+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "So now you know the value of a.  And the problem originally told you that:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+a+%2B+15 ALIGN=MIDDLE  ALT=\"x+=+a+%2B+15\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Substitute 9 for a and you have:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+9+%2B+15+=+24 ALIGN=MIDDLE  ALT=\"x+=+9+%2B+15+=+24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "So the answer to your problem is that x = 24.  You also know that a = 9, and since <BR>\n" );
document.write( "s = a - 1, you know that s = 9 - 1 = 8.  And since you were told that x = 3s you can check<BR>\n" );
document.write( "by substituting 8 for s and get x = 3s = 3*8 = 24.  So that checks the problem also.<BR>\n" );
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document.write( "Everything seems to work which helps to confirm that x = 24 is correct. </SPAN>\n" );
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