document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026191>Question 1026191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One eighth of Emilia's coins are quarters and the rest are nickels. If the total value of her coins is $3.60, how many of each type of coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642634 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers of quarters and nickels, q and n.<BR>\n" );
document.write( "Since one eighth of Emilia's coins are quarters and the rest are nickels, we have n = 7q, or 7q - n = 0.  <BR>\n" );
document.write( "Our value equation is<BR>\n" );
document.write( "25q + 5n = 360 (we work in cents)<BR>\n" );
document.write( "Now multiply the top equation by five and add and get<BR>\n" );
document.write( "25q + 5n = 360<BR>\n" );
document.write( "+(35q - 5n = 0)<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "60q = 360<BR>\n" );
document.write( "q = 6 quarters  and then<BR>\n" );
document.write( "n = 42 nickels </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );