document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027411>Question 1027411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Viva has a total of 59 coins all of which are either dime or nickels the total of the coin is 4.65 find the number of each type of coin  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642620 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642620\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers of nickels and dimes, n and d.  Then we have<BR>\n" );
document.write( "n + d = 59 and the value equation is<BR>\n" );
document.write( "5n + 10d = 465  (we will work in cents)<BR>\n" );
document.write( "Now multiply the top equation by five and subtract...we get<BR>\n" );
document.write( "5n + 10d = 465<BR>\n" );
document.write( "-(5n + 5d = 295)<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "5d = 170<BR>\n" );
document.write( "d = 34 dimes and thus<BR>\n" );
document.write( "n = 25 nickels </SPAN>\n" );
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