document.write( "Question 88351: find the partial decomposition for the rational expression. 3/2x(3x+1) 3/2x(3x+1)=?/2x+?/3x+1 the question mark represent a blank space \n" ); document.write( "
Algebra.Com's Answer #64262 by stanbon(75887)\"\" \"About 
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find the partial decomposition for the rational expression. 3/2x(3x+1) 3/2x(3x+1)=?/2x+?/3x+1 the question mark represent a blank space\r
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\n" ); document.write( "3/2x(3x+1) = A/2x + B/(3x+1)
\n" ); document.write( "= [A(3x+1)+B(2x)]/[2x(3x+1)]
\n" ); document.write( "Since the denominators are equal the numerators must be equal:
\n" ); document.write( "[3Ax+A + 2Bx] = 3
\n" ); document.write( "(3A+2B)x + A = 0x + 3
\n" ); document.write( "A = 3
\n" ); document.write( "Therefore:
\n" ); document.write( "3A+2B = 0
\n" ); document.write( "3*3 + 2B = 0
\n" ); document.write( "2B = - 9
\n" ); document.write( "B = -4.5
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\n" ); document.write( "Final Answer:
\n" ); document.write( "3/2x(3x+1) = 3/2x - 4.5/(3x+1)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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