document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027401>Question 1027401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 2% salt solution must be mixed with 100 gallons of a 8% salt solution to obtain a 3% salt solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642599 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of gallons of 2% salt solution, x.<BR>\n" );
document.write( "Then the setup looks like this:<BR>\n" );
document.write( ".02x + .08(100) = .03(100 + x)<BR>\n" );
document.write( "Now we solve for x.<BR>\n" );
document.write( ".02x + 8 = 3 + .03x<BR>\n" );
document.write( "Subtract 3 and subtract .02x from both sides and get<BR>\n" );
document.write( "5 = .01x<BR>\n" );
document.write( "Divide by .01 and get<BR>\n" );
document.write( "x = 500 gallons of 2% salt solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );