document.write( "Question 1027253: The sum of 3 numbers is 3. Twice the first minus the second is 3 more than the third. The third is five less than the first. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #642594 by Cromlix(4381) You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the First number = x \n" ); document.write( "The third is five less than the first \n" ); document.write( "Third = x - 5 \n" ); document.write( "Twice the first minus the second is \n" ); document.write( "3 more than the third. \n" ); document.write( "2(x) - Second = 3 + (x - 5) \n" ); document.write( "2x - Second = 3 + x - 5 \n" ); document.write( "2x - Second = -2 + x \n" ); document.write( "-Second = -2 + x - 2x \n" ); document.write( "Second = 2 - x + 2x \n" ); document.write( "Second = 2 + x \n" ); document.write( ".............To recap. \n" ); document.write( "First number = x \n" ); document.write( "Second number = 2 + x \n" ); document.write( "Third number = x - 5\r \n" ); document.write( "\n" ); document.write( "Total of 3 \n" ); document.write( "x + (2 + x) + (x - 5) = 3 \n" ); document.write( "x + 2 + x + x - 5 = 3 \n" ); document.write( "Collect like terms: \n" ); document.write( "x + x + x = 3 - 2 + 5 \n" ); document.write( "3x = 6 \n" ); document.write( "x = 2 \n" ); document.write( "First number = 2 \n" ); document.write( "Second number = 4 \n" ); document.write( "Third number = -3 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " \n" ); document.write( " |