document.write( "Question 1027384: A rectangular piece of metal is 10 in longer than it is wide. Squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 528in^3​, what were the original dimensions of the piece of​ metal? \n" ); document.write( "
Algebra.Com's Answer #642574 by josgarithmetic(39617)\"\" \"About 
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w and L, the dimensions.
\n" ); document.write( "L=w+10, and w, again the same dimensions, using the given description.\r
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\n" ); document.write( "\n" ); document.write( "Folding the flaps, the base of the box is (L-2*2)(w-2*2) inch^2 and the height is 2 inches.\r
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\n" ); document.write( "\n" ); document.write( "This means the volume is \"2%28L-4%29%28w-4%29=528\".
\n" ); document.write( "Substitute for L, simplify the equation, and solve for w.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28w%2B10-4%29%28w-4%29=528\"
\n" ); document.write( "\"%28w%2B6%29%28w-4%29=528%2F2\"
\n" ); document.write( "\"w%5E2%2B4w-24=264\"
\n" ); document.write( "\"w%5E2%2B4w-24-264=0\"
\n" ); document.write( "\"highlight_green%28w%5E2%2B4w-288=0%29\"-----------Continue from here.....
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