document.write( "Question 1027384: A rectangular piece of metal is 10 in longer than it is wide. Squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 528in^3, what were the original dimensions of the piece of metal? \n" ); document.write( "
Algebra.Com's Answer #642574 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! w and L, the dimensions. \n" ); document.write( "L=w+10, and w, again the same dimensions, using the given description.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Folding the flaps, the base of the box is (L-2*2)(w-2*2) inch^2 and the height is 2 inches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means the volume is \n" ); document.write( "Substitute for L, simplify the equation, and solve for w.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |