document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027305>Question 1027305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I'm having trouble solving and figuring what to do for this problem:\r<BR>\n" );
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document.write( "Solve log base 7 of x + log base 7 of 2 = log base 7 of (x+6)\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642517 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  log base 7 of x + log base 7 of 2 = log base 7 of (x+6)<BR>\n" );
document.write( "log 7 (2x)=log 7(x+6), because when you add logs it is the same as multiplying what the log is of.<BR>\n" );
document.write( "raise everything to the 7 th power.<BR>\n" );
document.write( "2x=x+6<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "log7(6)+log7(2)=log7(12)<BR>\n" );
document.write( "0.921+0.356 is about equal to 1.277 </SPAN>\n" );
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