document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027300>Question 1027300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> give that (-3,-5)and(-1,-4) are points on the same line find a point-slope form of the equation for this line I know that the slope is 1/2 then i get lost in how to put it in point-slope form </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642511 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope of the line is the change in y over the change in x.  This is 1/2 as you show.<BR>\n" );
document.write( "Point slope formula<BR>\n" );
document.write( "y-y1=m(x-x1).  m is the slope.  Use either point for the x1 or y1.  You will get the same result.<BR>\n" );
document.write( "y- (-5))=(1/2)(x-(-3))<BR>\n" );
document.write( "y+5=(1/2)(x+3)<BR>\n" );
document.write( "y+5=(1/2)x+3/2<BR>\n" );
document.write( "y=(1/2)x-(7/2)<BR>\n" );
document.write( "using the other point<BR>\n" );
document.write( "y-(-4))=(1/2)(x-(-1))<BR>\n" );
document.write( "y+4=(1/2)(x+1)<BR>\n" );
document.write( "y+4=(1/2)x +(1/2)<BR>\n" );
document.write( "y=(1/2)x-(7/2) </SPAN>\n" );
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