document.write( "Question 1027261: \"+25y%5E2-4x%5E2-8x-104=0+\"\r
\n" ); document.write( "\n" ); document.write( "Idk how to find the center teach me please
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Algebra.Com's Answer #642487 by purpleoj(8)\"\" \"About 
You can put this solution on YOUR website!
Okay.
\n" ); document.write( "I'm going to start by factoring the -4 away from the \"x\"s and -104.\r
\n" ); document.write( "\n" ); document.write( "\"+25y%5E2-4%28x%5E2%2B2x%2B26%29=0+\"\r
\n" ); document.write( "\n" ); document.write( "Now, you want to make the X section into a binomial which can be squared easily, and you start by dividing the middle number by 2 and then squaring it to get 1. (sorry if that bit was unclear)\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2%2B2x%2B1%2B%2825%29+\"\r
\n" ); document.write( "\n" ); document.write( "Now you have 25 left over. This section of your equation now looks like:\r
\n" ); document.write( "\n" ); document.write( "\"+-4%28%28x%2B1%29%5E2%2B25%29+\"\r
\n" ); document.write( "\n" ); document.write( "Multiply the -4 and 25 to get -100 (which I will move to the other end of the equation). Your entire equation now looks like:\r
\n" ); document.write( "\n" ); document.write( "\"+25y%5E2-4%28x%2B1%29%5E2=100+\"\r
\n" ); document.write( "\n" ); document.write( "However, this is not simplified. Now, divide both sides by 100, and you get:\r
\n" ); document.write( "\n" ); document.write( "\"+y%5E2%2F4-%28x%2B1%29%5E2%2F25=1+\"\r
\n" ); document.write( "\n" ); document.write( "If it was just an \"+x%5E2+\", our center would be at the origin (0,0). However, since it is \"+%28x%2B1%29%5E2+\", we subtract 1 from the center x-coordinate out the 1 in \"+%28x%2B1%29%5E2+\". The y-coordinate was unaffected.\r
\n" ); document.write( "\n" ); document.write( "Your center coordinate is (-1,0).\r
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