document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027195>Question 1027195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If  combined age of family is 81 and the father is 3 years older than mother and mother is 27 years older from son then find the age of all three separatly<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642448 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If combined age of family is 81 and the father is 3 years older than mother and mother is 27 years older from son then find the age of all three separatly<BR>\n" );
document.write( "let x= age of son<BR>\n" );
document.write( "x+27=age of mother<BR>\n" );
document.write( "x+27+3= age of father<BR>\n" );
document.write( "x+x+27+x+27+3=81<BR>\n" );
document.write( "3x=24<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( " age of son=8<BR>\n" );
document.write( "age of mother=35<BR>\n" );
document.write( "x+27+3= age of father=38 </SPAN>\n" );
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