document.write( "Question 1027191: A and B are independent events. If P(A and B) is 0.4 and P(A or B) is 0.9 find P(A) and P(B) where P(A) is greater than P(B)
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Algebra.Com's Answer #642442 by robertb(5830)\"\" \"About 
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Let x = P(A) and y = P(B).
\n" ); document.write( "Then from the addition law of probability, \r
\n" ); document.write( "\n" ); document.write( "0.9 = x+y - 0.4 ==> x+y = 1.3
\n" ); document.write( "Also, since A, B are independent events, P(A∩B) = P(A)P(B) = xy = 0.4\r
\n" ); document.write( "\n" ); document.write( "==> x(1.3 - x) = 0.4, or \"x%5E2+-+1.3x+%2B0.4+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Directly using the quadratic formula, we get the solutions x = 0.8, 0.5.\r
\n" ); document.write( "\n" ); document.write( "Since x > y, it follows that P(A) = 0.8 and P(B) = 0.5.
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