document.write( "Question 1027132: Dilbert invests a total of $35,500 in two accounts paying 5% and 7% annual interest, respectively. How much was invested in each account if, after one year, the total interest was $2,105.00.\r
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document.write( "______$ was invested at 5% and
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document.write( "_______$ was invested at 7%. \n" );
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Algebra.Com's Answer #642423 by mananth(16946) You can put this solution on YOUR website! Part I 5.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 7.00% per annum ------------ Amount invested = y \n" ); document.write( " 35500 \n" ); document.write( "Interest----- 2105 \n" ); document.write( " \n" ); document.write( "Part I 5.00% per annum ---x \n" ); document.write( "Part II 7.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 35500 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "5.00% x + 7.00% y= 2105 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5 x + 7 y= 210500.00 --------2 \n" ); document.write( "Multiply (1) by -5 \n" ); document.write( "we get \n" ); document.write( "-5 x -5 y= -177500.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 2 y= 33000 \n" ); document.write( "divide by 2 \n" ); document.write( " y = 16500 \n" ); document.write( "Part I 5.00% $ 19000 \n" ); document.write( "Part II 7.00% $ 16500 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "19000 --------- 5.00% ------- 950.00 \n" ); document.write( "16500 ------------- 7.00% ------- 1155.00 \n" ); document.write( "Total -------------------- 2105.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |