document.write( "Question 1027171: Hi, I'm having trouble solving and figuring out what to do with this problem:\r
\n" ); document.write( "\n" ); document.write( "A rectangular picture 16 inches by 20 inches has a frame of uniform width. Find the width of the frame if the total area of the picture and the frame is 672 square inches.\r
\n" ); document.write( "\n" ); document.write( "Thank you.
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Algebra.Com's Answer #642419 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Length of photo = 20 in
\n" ); document.write( "Width = 16 in
\n" ); document.write( "Total area = 672
\n" ); document.write( "Area of picture DISABLED_event_only= 320 m^2
\n" ); document.write( "Area of border = 352 m^2
\n" ); document.write( "Length of picture+border= 20 + 2 x
\n" ); document.write( "width of picture+border = 16 + 2 x
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\n" ); document.write( "( 20 + 2 x ) ( 16 + 2 x ) + -320 = 352
\n" ); document.write( "
\n" ); document.write( " 320 + 40 x + 32 x + 4 X^2 + -320 = 352
\n" ); document.write( " 4 X^2 + 72 x + -352 = 0
\n" ); document.write( " Find the roots of the equation by quadratic formula
\n" ); document.write( " a= 4 b= 72 c= -352
\n" ); document.write( " b^2-4ac= 5184 - -5632
\n" ); document.write( " b^2-4ac= 10816 \"sqrt%28%0910816%09%29\"= 104
\n" ); document.write( " \"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( " \"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( " x1=( -72 + 104 )/ 8
\n" ); document.write( " x1= 4
\n" ); document.write( " x2=( -72 -104 ) / 8
\n" ); document.write( " x2= -15.5
\n" ); document.write( " Ignore negative value
\n" ); document.write( " width of border 4 in
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