document.write( "Question 1027091: 2. The incomplete table at right is a discrete random variable x's probability distribution, where x is the number of courses taken by randomly selected undergraduate student. Answer the following: \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Table : > http://prntscr.com/alqvcp
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " (a) Determine the value that is missing in the table.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " (b) Explain the meaning of P(x >2) as it applies to the context of this problem.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " (c) Determine the value of P(x ≤ 3):
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " (d) Find the probability that x is at least 2.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " (e) Find the mean (expected value) and standard deviation of this probability distribution.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #642394 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
(a) 1 - .15 - .41 - .18 - .15 = .11\r
\n" ); document.write( "\n" ); document.write( "(b) P(x>2) = 0.44 ==> there is 44% probability that a randomly selected undergraduate student will take 3 or more courses.\r
\n" ); document.write( "\n" ); document.write( "(c) P(x ≤ 3) = 0.74\r
\n" ); document.write( "\n" ); document.write( "(d) 1-0.15 = 0.85\r
\n" ); document.write( "\n" ); document.write( "(e) E(X) = 1*0.14 + 2*0.41 + 3*0.18 + 4*0.11 + 5*0.15 = 2.69\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "==> standard deviation = \"sqrt%281.6739%29+=+1.2938\"
\n" ); document.write( "
\n" );