document.write( "Question 1027118: Trian A leaves Bosotn for NY at 7 am going 30mph. Trian B leaves NY for Boston at 8:30 am going 80mph. If the distance from Boston to NY is 210miles when did the trains pass each other? \n" ); document.write( "
Algebra.Com's Answer #642372 by ankor@dixie-net.com(22740)\"\" \"About 
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Train A leaves Boston for NY at 7 am going 30mph.
\n" ); document.write( " Train B leaves NY for Boston at 8:30 am going 80mph.
\n" ); document.write( " If the distance from Boston to NY is 210miles, when did the trains pass each other?
\n" ); document.write( ":
\n" ); document.write( "let t = travel time until they met of the A train
\n" ); document.write( "train B left 1.5 hrs later, therefore
\n" ); document.write( "(t-1.5) = travel time of B when they met
\n" ); document.write( ":
\n" ); document.write( "When they meet, the sum of their distances will equal 210 mi
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "30t + 80(t-1.5) = 210
\n" ); document.write( "30t + 80t - 120 = 210
\n" ); document.write( "110t = 210 + 120
\n" ); document.write( "t = 330/110
\n" ); document.write( "t = 3 hrs
\n" ); document.write( ":
\n" ); document.write( "When train A travels for 3 hrs the time will be 10 AM when they meet
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