document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027110>Question 1027110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Y=1/2x^2+5x+1 find the vertex, x intercepts and axis of symmetry  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642366 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The vertex has an x-value of -b/2a<BR>\n" );
document.write( "Here, that is -5/1=-5 for x and y is +12.5-25+1=-11.5<BR>\n" );
document.write( "(-5,13.5)<BR>\n" );
document.write( "x-inercepts--set y=0<BR>\n" );
document.write( "1/2 x^2+5x+1=0<BR>\n" );
document.write( "multiply by 2 to clear fractions<BR>\n" );
document.write( "x^2+10x+2=0<BR>\n" );
document.write( "x=(1/2)(-10 +/- sqrt (100-8)); sqrt 92=2 sqrt(23)<BR>\n" );
document.write( "x=-5+/- sqrt (23); numerically, it is -0.204 and -9.80<BR>\n" );
document.write( "Axis of symmetry is around the vertex, and that is at -5.<BR>\n" );
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