document.write( "Question 1026910: The base of a triangular sail is 16 m shorter than its height. The area is 130m squared. Find the base and height of the sail. \n" ); document.write( "
Algebra.Com's Answer #642284 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Area of triangle = 1/2(base x height)
\n" ); document.write( "Make height = x
\n" ); document.write( "Base = x - 16
\n" ); document.write( "Area = 1/2(base x height)
\n" ); document.write( "130 = 1/2((x - 16) * x) (* times)
\n" ); document.write( "130 = 1/2(x^2 - 16x)
\n" ); document.write( "130 = x^2/2 - 8x
\n" ); document.write( "Put into ax^2 + bx + c = 0 form
\n" ); document.write( "x^2/2 - 8x - 130 = 0
\n" ); document.write( "Multiply through by 2
\n" ); document.write( "x^2 - 16x - 260 = 0
\n" ); document.write( "Factorise:
\n" ); document.write( "(x + 10)(x - 26)= 0
\n" ); document.write( "x + 10 = 0
\n" ); document.write( "x = -10 (disregard as -ve)
\n" ); document.write( "x - 26 = 0
\n" ); document.write( "x = 26
\n" ); document.write( "Height of sail = 26m
\n" ); document.write( "Base of sail = 10m
\n" ); document.write( "Hope this helps :-)
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