document.write( "Question 1026990: A man invests N1800 at simple interest. After 2 years th amount (including interest) is N1980. Fine the rate perbent per annum \n" ); document.write( "
Algebra.Com's Answer #642275 by Theo(13342)\"\" \"About 
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simple interest formula ia:\r
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\n" ); document.write( "\n" ); document.write( "i = p * r * n\r
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\n" ); document.write( "\n" ); document.write( "i = interest
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\n" ); document.write( "r = rate of interest per time period
\n" ); document.write( "n = number of time periods\r
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\n" ); document.write( "\n" ); document.write( "man invests 1800
\n" ); document.write( "after 2 years he has 1980\r
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\n" ); document.write( "\n" ); document.write( "his interest earned is 1980 - 1800 = 180.\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "p = 1800
\n" ); document.write( "i = 180
\n" ); document.write( "n = 2\r
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\n" ); document.write( "\n" ); document.write( "formula of i = p * r * n becomes:\r
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\n" ); document.write( "\n" ); document.write( "180 = 1800 * r * 2\r
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\n" ); document.write( "\n" ); document.write( "solve for r to get r = 180 / 1800 / 2 = .05\r
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\n" ); document.write( "\n" ); document.write( "his interest rate is .05 per year.\r
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\n" ); document.write( "\n" ); document.write( "that's 5% per year.\r
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\n" ); document.write( "\n" ); document.write( "at 5% interest per year, he makes 1800 * .05 = 90 interest each year.\r
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\n" ); document.write( "\n" ); document.write( "in 2 years that becomes 180.\r
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\n" ); document.write( "\n" ); document.write( "with simple interest, you are only earning interest on the original principal each other.\r
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\n" ); document.write( "\n" ); document.write( "this gives you the same amount of interest each year.
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