document.write( "Question 1026988: A newspaper carrier had $6.65 in change. He has ten more quarters than dimes but two times as many nickels as quarters. How many coins of each type does he have? \n" ); document.write( "
Algebra.Com's Answer #642263 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "A newspaper carrier had $6.65 in change. He has ten more quarters than dimes but two times as many nickels as quarters. How many coins of each type does he have?
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document.write( "Let q = # of quarters, d = # of dimes and n = # of nickels.\r\n" );
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document.write( "Then what you have from the condition is \r\n" );
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document.write( "d = q - 10  and  n = 2q.     (1)\r\n" );
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document.write( "Next, you have the \"value\" equation\r\n" );
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document.write( "5n + 10d + 25q = 665.        (2)\r\n" );
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document.write( "Substitute (1) into the \"value\" equation. You will get a single equation for q:\r\n" );
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document.write( "5*(2q) + 10*(q-10) + 25q = 665.\r\n" );
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document.write( "Simplify and solve it for q:\r\n" );
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document.write( "10q + 10q - 100 + 25q = 665,\r\n" );
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document.write( "45q = 665 + 100,\r\n" );
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document.write( "45q = 765,\r\n" );
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document.write( "q = \"765%2F45\" = 17.\r\n" );
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document.write( "Now from (1)  d = q - 10  = 17 - 10 = 7  and  n = 2q = 2*17 = 34.\r\n" );
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document.write( "Answer.  34 nickels,  7 dimes  and  17 quarters.\r\n" );
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