document.write( "Question 1026988: A newspaper carrier had $6.65 in change. He has ten more quarters than dimes but two times as many nickels as quarters. How many coins of each type does he have? \n" ); document.write( "
Algebra.Com's Answer #642263 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A newspaper carrier had $6.65 in change. He has ten more quarters than dimes but two times as many nickels as quarters. How many coins of each type does he have? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let q = # of quarters, d = # of dimes and n = # of nickels.\r\n" ); document.write( "\r\n" ); document.write( "Then what you have from the condition is \r\n" ); document.write( "\r\n" ); document.write( "d = q - 10 and n = 2q. (1)\r\n" ); document.write( "\r\n" ); document.write( "Next, you have the \"value\" equation\r\n" ); document.write( "\r\n" ); document.write( "5n + 10d + 25q = 665. (2)\r\n" ); document.write( "\r\n" ); document.write( "Substitute (1) into the \"value\" equation. You will get a single equation for q:\r\n" ); document.write( "\r\n" ); document.write( "5*(2q) + 10*(q-10) + 25q = 665.\r\n" ); document.write( "\r\n" ); document.write( "Simplify and solve it for q:\r\n" ); document.write( "\r\n" ); document.write( "10q + 10q - 100 + 25q = 665,\r\n" ); document.write( "\r\n" ); document.write( "45q = 665 + 100,\r\n" ); document.write( "\r\n" ); document.write( "45q = 765,\r\n" ); document.write( "\r\n" ); document.write( "q = \n" ); document.write( " \n" ); document.write( " |